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Theory

The circuit in Fig. 2.4 is a Common Emitter (CE) Amplifier.
  
Figure 2.4: Common Emitter Amplifier
\begin{figure}
\centering{
\fbox {\psfig{file=./413_figs/fig2_04.ps,width=5.0in}}
}\end{figure}

As discussed above, with the CE amplifier, we first use R1, R2, C1, and C2 to set up a DC operating point with vin=0. The purpose of C1 and C2 is to isolate the DC operating point currents and voltages from the rest of the world, i.e, the signal source and the load. After establishing a DC operating point, an input signal is applied to the base coupling capacitor C1. For large enough frequencies, the signal will pass through the coupling capacitor and enter the base. This will result in variations in the bias conditions in accordance with the input signal. The variation of bias conditions at the collector is then passed through the capacitor C2, which is taken to be vout. The small signal voltage gain is then considered to be $\frac{v_{out}}{v_{in}}$.

For simple CE amplifiers, we have to first establish a DC bias condition which means that we have to choose bias resistors R1 and R2 that give us appropriate values for VC, VB and VE. The DC bias point is usually established to allow for a large variation or swing in vout. To provide this large swing in vout, a bias network is chosen so that $V_C \approx \frac{V_{CC}}{2}$. In addition, VB and VE are chosen to be relatively small to make sure that VC > VB and the BJT does not enter the saturation region. (Saturation occurs when both the base-emitter and the base-collector junction are forward biased.)

If the values of R1,R2,RE,RC and VCC are already known, (which is the situation for analyzing existing circuits) the DC bias conditions can be determined by first replacing the voltage divider with its Thevenin equivalent, and then by directly applying loop equations to the circuit while vin=0. To see this consider the circuit in Fig. 2.5.


  
Figure 2.5: Determining DC Bias
\begin{figure}
\centering{
\fbox {\psfig{file=./413_figs/fig2_05.ps,width=4.0in}}
}\end{figure}

Using KVL on the base emitter loop, we obtain

 
VBB = IBRB+IE RE + VBE (22)

where RB=R1||R2 and $V_{BB}=\frac{V_{CC}R_2}{R_1+R_2}$.

The B-E loop gives one equation and three unknowns. We can easily reduce the number of unknowns by making the very good approximations $I_C \approx I_E$, and VBE=0.7V. Using these approximations and recalling that $\beta I_B=I_C$,we can obtain the following equation for IC in terms of known parameters.
\begin{displaymath}
I_C=\frac{V_{BB}-0.7}{\frac{R_B}{\beta}+R_E}\end{displaymath} (23)
With IC determined, VC and VE are readily obtained by observing that:

VC=VCC-ICRC

(24)

VE=IERE

(25)

VB=VE+0.7

(26)


next up previous contents
Next: Experiment: CE Amp DC Up: Common Emitter Amplifier: DC Previous: Common Emitter Amplifier: DC
Neil Goldsman
10/23/1998